Dear Students,

I would like to specify from where that equation, Hi-5*t^2 comes from.

This term, 5*t^2, it comes from Physics.

The general equation is : H(t) = H_i + v_i*t + 1/2*(g)*t^2

H(t) - height as a function of time

H_i - initial height, which in our case is 45 meters

v_i - initial velocity, in our case it is 0 m/s (the ball starts at rest)

g - acceleration due to gravity (-10 m/s^2). In fact, it is -9.81 m/s^2; however, let's just assume that it is -10 m/s^2 for simplicity.

t - time [seconds]

And that is why, you are left with the following equation:

H(t) = 45 + 0*t + 1/2*(-10)*t^2

H(t) = 45 - 5*t^2

Best Regards,

Mark